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Solve the recurrence relation: T(n)=T(n/2)+T(n^0.5)+n
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Mar 2
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Asymptotic Analysis
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Simple guess that anyone can make is that T(n) = O(n). This can be proved using PMI.
Further, since T(n) includes n, we know that T(n) = Big Omega(n). Therefore, we can reach the conclusion that T(n) = Theta(n).
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Mar 20
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Amrinder Arora
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