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Asymptotically compare recurrence relations T and R.  Express your answer by writing asymptotic relation between T and R.

T(n) = 14 T(n/4) + O(n).              R(n) = 7 R(n/2) + O(n).

in Asymptotic Analysis by AlgoMeister (1.6k points)

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Using masters theorem: a=14 b=4
n^log_4(14) = n^1.9 > n
T(n) = O(n^log_4(14))

Using masters theorem: a=7 b=2
n^log_2(7) = n^2.8 > n
R(n) = O(n^log_2(7))

T(n) = o(R(n) as n^1.9 < n^2.8
by AlgoMeister (688 points)
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